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Coverage factor k explained: why k = 2 means about 95 %

The coverage factor multiplies combined standard uncertainty to give expanded uncertainty. k = 2 is about 95 %, but only when the distribution is normal.

MetrologyValiTrac AI editorialUpdated 2026-10-083 min read

A combined standard uncertainty u_c corresponds to about 68 % coverage for a normal distribution — too small an interval for most practical statements. The expanded uncertainty U = k·u_c widens it: k = 2 gives roughly 95 %, k = 3 roughly 99.7 %.

When k = 2 is not 95 %

If the combined uncertainty is dominated by a single rectangular component, or the Type A evaluation is based on very few observations, the output distribution is not normal and k = 2 may not deliver 95 %. The GUM's Welch–Satterthwaite formula for effective degrees of freedom, or a Monte Carlo evaluation, addresses this.

Reading certificates

An uncertainty quoted without k cannot be compared with one quoted at k = 2. Ask for it; accredited certificates are required to state it.

The numbers behind k

For a normal output distribution, k is simply how many standard uncertainties wide the interval is, and the coverage follows from the normal distribution.

Coverage factors for a normal distribution
kCoverageWhere you see it
168.27 %u_c itself; not usually reported as an interval
1.64590 %Occasionally, in some testing fields
1.9695 %The exact value; k = 2 is used in its place by convention
295.45 %The near-universal default on calibration certificates
2.57699 %Where a higher confidence is contractually required
399.73 %Safety-critical work
Coverage factors for a normal distribution

The convention of k = 2 rather than 1.96 is deliberate. It is a round number, it is marginally conservative, and it is what ILAC and the accreditation bodies expect, so certificates across the world are comparable without anyone doing arithmetic.

Two cases where k = 2 is not 95 %

The first is a budget dominated by a single rectangular component — a coarse display resolution, for example. A rectangular distribution has no tails, and its entire range lies within about 1.73 standard uncertainties of the centre. If one such term dominates, multiplying u_c by 2 produces an interval covering close to 100 % rather than 95 %: over-conservative, and not what the certificate claims.

The second is a Type A component from very few observations. A standard deviation from four readings is itself highly uncertain, and the output distribution has heavier tails than normal. The GUM's answer is to compute effective degrees of freedom by the Welch–Satterthwaite formula and take k from the t-distribution: with ν_eff of 6, k for 95 % is 2.45, not 2 — a 23 % wider interval.

Reading and writing it

  • An uncertainty quoted without k cannot be compared with one quoted at k = 2. Ask for it; accredited certificates are required to state it.
  • Write approximately 95 %, not 95 %, unless effective degrees of freedom were actually evaluated. The approximation is in the coverage, and the word is doing real work.
  • Dividing by k to recover u_c from someone else's certificate is correct and routine — that is exactly what you do when their result becomes an input to your budget.
  • Where k is not 2, say why on the certificate. A k of 2.45 with no explanation looks like an error rather than a Welch–Satterthwaite result.

Frequently asked questions

Why do some certificates quote k = 2.1 or 2.3?
Because the effective degrees of freedom were low and the laboratory used the t-distribution to achieve 95 % coverage rather than assuming normality.
Can I convert U at k = 2 to a standard uncertainty?
Yes: divide by k. U = 0.04 °C at k = 2 gives u = 0.02 °C.

References

  1. [1]JCGM 100:2008 — Guide to the expression of uncertainty in measurement (GUM)

General technical guidance written against the cited sources. It is not regulatory or legal advice and does not replace the applicable standard, guideline or a qualified reviewer's judgement.

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